Question

3*(m+1) *(m-1) -4*(2+1,5m) *(1,5m-2) +6m*(m-1) =31

Answer 1

Ответ:

m=-2

Пошаговое объяснение:

3m^2-3-9m^2+16+6m^2-6m=31

19-6m=31

-6m=31-19

-6m=12

m=12\-6

m=-2

Answer 2

Let's solve the given equation step by step:

The equation is:

3*(m+1)(m-1) - 4(2+1.5m)(1.5m-2) + 6m(m-1) = 31

1. Distribute the terms inside the parentheses:

   3*(m^2 - 1) - 4*(3 + 3m - 3m + 2) + 6m*(m - 1) = 31

2. Simplify within each set of parentheses:

   3m^2 - 3 - 12 + 12 - 12m + 8 + 6m^2 - 6m = 31

3. Combine like terms:

   3m^2 + 6m^2 - 12m - 6m - 3 + 8 = 31

   9m^2 - 18m + 5 = 31

4. Move all terms to one side of the equation:

   9m^2 - 18m + 5 - 31 = 0

   9m^2 - 18m - 26 = 0

5. The equation is now in the quadratic form. We can solve it using the quadratic formula:

   m = (-b ± √(b^2 - 4ac)) / 2a

   where a = 9, b = -18, and c = -26.

   Plugging in these values:

   m = (18 ± √((-18)^2 - 4 * 9 * -26)) / (2 * 9)

   m = (18 ± √(324 + 936)) / 18

   m = (18 ± √1260) / 18

   m = (18 ± √(4 * 315)) / 18

   m = (18 ± 2√315) / 18

6. Further simplifying:

   m = (9 ± √315) / 9

7. The solutions for m are:

   m = (9 + √315) / 9 m = (9 - √315) / 9

These are the solutions for the given equation. They can be approximated using a calculator to get numerical values.