Question

-3(2,1z-4)-4,2=1,2(-5z+0,5) 8(0,7x-4)-2(0,2x-3)=-39

Answer 1

-3(2,1z-4)-4,2 = 1,2(-5z+0,5)

-6,3z +12 -4,2 = -6z +0,6

-6,3z +6z = 0,6 -12 +4,2

-0,3z = -7,2

0,3z = 7,2

z = 7,2 ÷ 0,3

z = 72 ÷ 3

z = 24

Ответ: 24.

8(0,7x-4)-2(0,2x-3) = -39

5,6х -32 -0,4х +6 = -39

5,2х = -39 +32 -6

5,2х = -13

х = -13 ÷ 5,2

х = -130 ÷ 52

х = -2,5

Ответ: -2,5.

Answer 2

Let's solve the given equations step by step:

Equation 1: -3(2 + 1z - 4) - 4(2) = 1(2)(-5z + 0.5)

Simplifying the equation:

-3(-2 + z) - 8 = -10z + 1

Multiplying -3 with each term inside the parentheses:

6 - 3z - 8 = -10z + 1

Combining like terms:

-3z - 2 = -10z + 1

Moving all the terms involving z to one side and the constants to the other side:

-3z + 10z = 1 + 2

7z = 3

Dividing both sides by 7:

z = 3/7

Equation 2: 8(0.7x - 4) - 2(0.2x - 3) = -39

Simplifying the equation:

5.6x - 32 - 0.4x + 6 = -39

Combining like terms:

5.2x - 26 = -39

Moving the constant term to the other side:

5.2x = -39 + 26

5.2x = -13

Dividing both sides by 5.2:

x = -13/5.2

Simplifying the result:

x = -2.5

Therefore, the solution to the given equations is: x = -2.5 z = 3/7