Question

{ x + y = 680, { 10,8x +1,1 y = 580.

Answer 1

{x+у=680(умножим на - 108)

{10,8х+1,1у=580(умножим на 10)

{-108х-108у=-73440

{108х+11у=5800

Прибавляем столбиком при этом - 108х с 108х сокращаются:

-97у=-67640

$y = \frac{67640}{91}$

Подставляем вместо у:

$x + \frac{67640}{97} = 680$

$x = - \frac{1680}{97}$

Ответ:

$y = \frac{67640}{97} ; x = - \frac{1680}{97}$

Answer 2

The system of equations you provided is:

Equation 1: x + y = 680 Equation 2: 10.8x + 1.1y = 580

To solve this system of equations, we can use substitution or elimination method. Let's solve it using the substitution method.

Step 1: Solve Equation 1 for x in terms of y. x = 680 - y

Step 2: Substitute the value of x in Equation 2. 10.8(680 - y) + 1.1y = 580

Step 3: Simplify and solve for y. 7344 - 10.8y + 1.1y = 580 -9.7y = 580 - 7344 -9.7y = -6764 y = -6764 / -9.7 y ≈ 697.85

Step 4: Substitute the value of y back into Equation 1 to find x. x + 697.85 = 680 x ≈ 680 - 697.85 x ≈ -17.85

Therefore, the solution to the system of equations is approximately: x ≈ -17.85 y ≈ 697.85