Question

(х-3)(x+7)-(x+8)(x-4)=11​

Answer 1

Пошаговое объяснение:

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$( x - 3)(x + 7) - (x + 8)(x - 4) = 11 \\ {x}^{2} + 7x - 3x - 21 - ( {x}^{2} - 4x + 8x - 32) = 11 \\ {x}^{2} + 4x - 21 - {x}^{2} - 4x + 32 = 11 \\ 11 = 11$

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Answer 2

Let's solve the given equation step by step:

(х-3)(x+7) - (x+8)(x-4) = 11

First, let's expand the expressions: (x^2 + 7x - 3x - 21) - (x^2 - 4x + 8x - 32) = 11

Simplify each term: x^2 + 4x - 21 - x^2 + 4x - 32 = 11

Combine like terms: 8x - 53 = 11

Now, isolate the variable x by adding 53 to both sides: 8x = 64

Finally, solve for x by dividing both sides by 8: x = 8

So, the solution to the equation is x = 8.