Question

2. 4/7(0,56-4,2y)+0,4=5/13(0,52-6,5y) 3. (3x-2) (4+1/3x)=0

Answer 1

Ответ:

2. у=5,2

3. х=2/3 ;  х=-12

Пошаговое объяснение:

2. 4/7(0,56-4,2y)+0,4=5/13(0,52-6,5y)

0,32-2,4у+0,4=0,2-2,5у

-2,4у+2,5у=0,2-0,32-0,4

0,1у=0,52

у=0,52:0,1

у=5,2

3. (3x-2) (4+1/3x)=0

3х-2=0 или 4+1/3x=0

3х=2              1/3х=-4

х=2/3              х=-12

Answer 2

Sure, I'd be happy to help you solve these equations step by step:

1. $\frac{4}{7} (0.56 - 4.2y) + 0.4 = \frac{5}{13} (0.52 - 6.5y)$:

   First, let's simplify the equation by distributing the fractions:

   $\frac{4 \cdot 0.56}{7} - \frac{4 \cdot 4.2y}{7} + 0.4 = \frac{5 \cdot 0.52}{13} - \frac{5 \cdot 6.5y}{13}$

   $0.224 - 0.6y + 0.4 = 0.2 - 2.5y$

   Combine the constants and the terms with $y$ on each side:

   $0.624 - 0.6y = 0.2 - 2.5y$

   Now, add $2.5y$ to both sides:

   $2.5y + 0.624 - 0.6y = 0.2$

   Simplify the left side:

   $1.9y + 0.624 = 0.2$

   Subtract $0.624$ from both sides:

   $1.9y = -0.424$

   Finally, divide by $1.9$:

   $y = -\frac{0.424}{1.9}$

   $y \approx -0.223$

2. $(3x - 2) \left(4 + \frac{1}{3}x\right) = 0$:

   To solve this equation, we'll use the zero product property. This property states that if the product of two factors is zero, then at least one of the factors must be zero. So, we'll set each factor equal to zero and solve for $x$:

   $3x - 2 = 0$ or $4 + \frac{1}{3}x = 0$

   Solve for $x$ in the first equation:

   $3x = 2$

   $x = \frac{2}{3}$

   Solve for $x$ in the second equation:

   $\frac{1}{3}x = -4$

   Multiply both sides by 3:

   $x = -12$

   So, the solutions are $x = \frac{2}{3}$ and $x = -12$.

If you have any more equations or questions, feel free to ask!