Question

3^2*4^3*12^2/9^2*6^3

Answer 1

Ответ:

3^2*4^3*12^2/9^2*6^3=9*64*144/81*216=82944/34992=2,37

Answer 2

Let's simplify the expression step by step:

1. Calculate the powers of each base:

   • $3^2 = 9$
   • $4^3 = 64$
   • $12^2 = 144$
   • $9^2 = 81$
   • $6^3 = 216$

2. Substitute these values back into the expression:

   $\frac{9 \cdot 64 \cdot 144}{81 \cdot 216}$

3. Calculate the numerator and denominator separately:

   Numerator: $9 \cdot 64 \cdot 144 = 82944$ Denominator: $81 \cdot 216 = 17496$

4. Finally, divide the numerator by the denominator:

   $\frac{82944}{17496} = 4.74$

So, $3^2 \cdot 4^3 \cdot 12^2 / 9^2 \cdot 6^3$ simplifies to approximately $4.74$.