Question

√㏒ (1-x) + 5 ㏒(1-x)=6

Answer 1

Ответ: у тебя есть ответ на 6 и 7 задание

Пошаговое объяснение:

Answer 2

Ответ:

x = -9

Пошаговое объяснение:

√㏒ (1 - x) = 6 - 5 ㏒ (1 - x)

㏒ (1 - x) = 36 - 60 ㏒ (1 - x) = 25 ㏒ (1 - x)²

㏒ (1 - x)  + 60 ㏒ (1 - x) - 25 ㏒ (1 - x)² = 36

61 ㏒ (1 - x) - 25 ㏒ (1 - x)² = 36

61t - 25t² = 36

t = 1

t = $\frac{36}{25}$

x = -9

x = -10$\sqrt[25]{10^{11} }$ + 1

Теперь проверим наши решения:

$\sqrt{log (1 - (-9))}$ + 5log (1 - (-9)) = 6

  $\sqrt{log (1 - (-10\sqrt[25]{10^{11} } + 1) )}$+ 5 log (1 -(-10 $\sqrt[25]{10^{11} }$+ 1)) = 6

после упрощения получим, что:

при x = -9:      6 = 6

при x = -10$\sqrt[25]{10^{11} }$ + 1:       8,4 = 6

Получаем, что возможно только х = -9

На будущие: пиши такие уравнения с пробелами, чтобы их было удобно читать

Answer 3

The equation you've provided is a nonlinear equation involving logarithms. It appears to be:

√(log(1-x)) + 5 * log(1-x) = 6

Unfortunately, this equation doesn't have a simple algebraic solution that can be expressed in terms of elementary functions. To solve it, you would typically need to use numerical methods or specialized software that can approximate the solution.

If you're looking for a numerical solution, you can use methods such as the Newton-Raphson method or software like MATLAB, Mathematica, or Python with libraries like SciPy to find an approximate value for 'x' that satisfies the equation. Here's an example of how you might solve it using Python and SciPy:

pythonCopy code
import numpy as np
from scipy.optimize import fsolve
from math import log

def equation(x):
    return np.sqrt(log(1 - x)) + 5 * log(1 - x) - 6

# Initial guess for the solution
initial_guess = 0.5

# Solve the equation numerically
solution = fsolve(equation, initial_guess)

print("Approximate solution:", solution)

Remember to use proper numerical methods to ensure accurate and reliable solutions, especially if the equation is complex or has multiple solutions.