Question

X+y=31. y+z=41. x+z=36​

Answer 1

Ответ:

2x+2y+2z=108

x+y+z=54

x=54-41=13

y=54-36=18

z=41-18=23

Answer 2

Ответ:13,18,23

Пошаговое объяснение:из 1 ур-я: х= 31- у, поставляем в 3 ур-я, получаем систему 2 уравнений: 31-у+z=36 и у+z=41, вкладываем два уравнения, имеем: 2z+37=77, отссюда 2z=46, z= 23.

Из уравнения x+z=36 получаем х+23=36, х=36-23, х=13

Из уравнения х+у=31 имеем 13+ у=31, отсюда у=31-13, у=18

Answer 3

To solve the system of equations:

1. X + y = 31
2. y + z = 41
3. x + z = 36

There are multiple ways to approach this problem. One common method is to use substitution or elimination. Let's use the substitution method:

From equation 1, we can solve for x in terms of y: x = 31 - y.

Substituting this value of x into equation 3, we get: (31 - y) + z = 36.

Simplifying, we have: 31 + z - y = 36.

Rearranging the equation, we get: z - y = 36 - 31.

This simplifies to: z - y = 5. This is equation 4.

Now, we can solve equations 2 and 4 simultaneously to find the values of y and z.

Subtracting equation 4 from equation 2, we have: (y + z) - (z - y) = 41 - 5.

Simplifying, we get: 2y = 36.

Dividing both sides by 2, we find: y = 18.

Substituting the value of y back into equation 4, we have: z - 18 = 5.

Adding 18 to both sides, we find: z = 23.

Now, we can substitute the values of y and z into equation 1 to find the value of x:

x + 18 = 31.

Subtracting 18 from both sides, we get: x = 13.

Therefore, the solution to the system of equations is x = 13, y = 18, and z = 23.