Question

Найдите f'(1),если f(x)= 6/x²

Answer 1

Ответ:

-12

Пошаговое объяснение:

$f'(x)=6*(-\frac{2x}{x^{4} }=-\frac{12}{x^{3} } \\\\f'(1)=-\frac{12}{1}=-12$

Answer 2

To find the derivative of the function f(x) = 6/x^2, we can use the power rule for differentiation. According to the power rule, if we have a function of the form f(x) = ax^n, where a and n are constants, the derivative is given by f'(x) = anx^(n-1).

Applying the power rule to the given function f(x) = 6/x^2, we have:

f'(x) = d/dx (6/x^2) = -12/x^3

Now, to find f'(1), we substitute x = 1 into the derivative:

f'(1) = -12/1^3 = -12/1 = -12

Therefore, f'(1) = -12.