Question

1(y-7)^2+y^2-12y+36 при y=3/2

Answer 1

Ответ:

50.5

Пошаговое объяснение:

1(y-7)²+y²-12y+36 = y²-14y+49+y²-12y+36 = 2y²-26y+85 при y = 3/2 = 1.5

2*(1.5)²-26*1.5+85 = 2*2.25-39+85 = 4.5-39+85 = 50.5

Answer 2

To find the value of the expression $1(y-7)^2 + y^2 - 12y + 36$ when $y = \frac{3}{2}$, you can substitute the value of $y$ into the expression and then simplify:

$1\left(\frac{3}{2}-7\right)^2 + \left(\frac{3}{2}\right)^2 - 12\left(\frac{3}{2}\right) + 36$

First, let's calculate the terms individually:

1. $\left(\frac{3}{2}-7\right)^2 = \left(-\frac{11}{2}\right)^2 = \frac{121}{4}$
2. $\left(\frac{3}{2}\right)^2 = \frac{9}{4}$
3. $12\left(\frac{3}{2}\right) = 18$

Now plug these values back into the expression:

$\frac{121}{4} + \frac{9}{4} - 18 + 36$

Now, add the fractions and constants together:

$\frac{121 + 9}{4} - 18 + 36$

$\frac{130}{4} - 18 + 36$

$\frac{65}{2} - 18 + 36$

$\frac{65}{2} + 18$

Now, add the fractions and constants:

$\frac{65 + 36}{2} = \frac{101}{2}$

So, when $y = \frac{3}{2}$, the expression $1(y-7)^2 + y^2 - 12y + 36$ evaluates to $\frac{101}{2}$.