Question

4х + 2у + 3*(1,9х+2,3х+4,5у) при х = 1, у = 0,2​

Answer 1

Раскроем скобки и приведём подобные слагаемые:

= 4х + 2у + 5,7х + 6,9х + 13,5у = (4х + 5,7х + 6,9х) + (2у + 13,5у) =

= 16,6х + 15,5у

при х = 1, у = 0,2

16,6 · 1 + 15,5 · 0,2 = 16,6 + 3,1 = 19,7

Ответ: 19,7.

Answer 2

To evaluate the expression $4x + 2y + 3(1.9x + 2.3x + 4.5y)$ with $x = 1$ and $y = 0.2$, simply substitute the values of $x$ and $y$ into the expression and perform the calculations step by step:

Given: $x = 1$, $y = 0.2$

Expression: $4x + 2y + 3(1.9x + 2.3x + 4.5y)$

Substitute the values of $x$ and $y$: $4(1) + 2(0.2) + 3(1.9(1) + 2.3(1) + 4.5(0.2))$

Now calculate each part of the expression: $4 + 0.4 + 3(1.9 + 2.3 + 0.9)$ $4 + 0.4 + 3(5.1)$ $4 + 0.4 + 15.3$ $19.7$

So, when $x = 1$ and $y = 0.2$, the value of the expression is $19.7$.