Question

1)P=2a+2b b=? 2)S=ab/2 a=? 3)F=9/25C+32 C=? 4)I=E/R+r E=?

Answer 1

Ответ:

1) P = 2a +2b

2b = P - 2a

b = P-2a /2

2) S =ab/2

ab = 2S

a= 2S/b

3) F =9/25C+32

F ( 25C+32 ) = 9

9 = 25FC + 32F

25FC = 32F - 9

C = 32F -9/ 25F

4) I = E/R+r

E = l ( R +r )

Пошаговое объяснение:

Answer 2

It seems like you have a set of equations and you're looking to solve for the indicated variables in each equation. Let's solve them one by one:

1. $P = 2a + 2b$ for $b$: To solve for $b$, isolate it on one side of the equation: $P = 2a + 2b \implies 2b = P - 2a \implies b = \frac{P - 2a}{2}$

2. $S = \frac{ab}{2}$ for $a$: To solve for $a$, isolate it on one side of the equation: $S = \frac{ab}{2} \implies 2S = ab \implies a = \frac{2S}{b}$

3. $F = \frac{9}{25}C + 32$ for $C$: To solve for $C$, isolate it on one side of the equation: $F = \frac{9}{25}C + 32 \implies \frac{9}{25}C = F - 32 \implies C = \frac{25}{9}(F - 32)$

4. $I = \frac{E}{R} + r$ for $E$: To solve for $E$, isolate it on one side of the equation: $I = \frac{E}{R} + r \implies \frac{E}{R} = I - r \implies E = R(I - r)$

These are the solutions for the respective variables in each equation. Just substitute the values of the other variables into these equations to find the values you're looking for.