Question

Е -3x^2+2x+6=-x^2+3x-(-3+2x^2)​

Answer 1

Ответ:

вот так думаю будет

Пошаговое объяснение:

может быть не точным

Answer 2

To solve the given equation, let's simplify and solve step by step:

The equation is: $-3x^2 + 2x + 6 = -x^2 + 3x - (-3 + 2x^2)$

First, let's simplify the right-hand side by distributing the negative sign: $-3x^2 + 2x + 6 = -x^2 + 3x + 3 - 2x^2$

Now combine like terms on the right-hand side: $-3x^2 + 2x + 6 = -3x^2 + 3x + 3$

At this point, we can see that the quadratic terms cancel out on both sides of the equation. We're left with a linear equation: $2x + 6 = 3x + 3$

Now, let's isolate the variable $x$ by subtracting $2x$ from both sides of the equation: $6 = x + 3$

Subtract $3$ from both sides to solve for $x$: $x = 3$

So, the solution to the equation is $x = 3$.