Question

Cos 190° Cos 10° + Sin 10° sin 190°​

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

Ответ:

Cos 190° Cos 10° + Sin 10° sin 190°​=cos(190-10)=cos180=-1

Answer 3

The expression you've provided involves trigonometric functions. We can simplify it using trigonometric identities. One of the identities that will be helpful here is the product-to-sum identity:

$\cos(A) \cos(B) + \sin(A) \sin(B) = \cos(A - B)$

In your case, $A = 190°$ and $B = 10°$. So, using the identity:

$\cos(190°) \cos(10°) + \sin(10°) \sin(190°) = \cos(190° - 10°)$

$= \cos(180°)$

Since the cosine function has a periodicity of $360°$, $\cos(180°) = -1$.

So, the simplified value of the expression is $-1$.