Question

(5 5/17+x)∙(5 1/(9 )-2 5/18)=0;

Answer 1

Ответ: так как второй сомножитель не равен нулю, то приравниваем к нулю первый сомножитель или 5 5/17+х=0 или х=-5 5/17

Пошаговое объяснение:

Answer 2

To solve the equation $(5\frac{5}{17}+x) \cdot (5\frac{1}{9}-2\frac{5}{18})=0$, you can use the zero product property, which states that if the product of two factors equals zero, then at least one of the factors must be equal to zero.

So, you need to set each factor equal to zero and solve for $x$:

1. $5\frac{5}{17} + x = 0$

First, subtract $5\frac{5}{17}$ from both sides to isolate (x):

$x = -5\frac{5}{17}$

2. $5\frac{1}{9} - 2\frac{5}{18} = 0$

To solve this, you can first find a common denominator for the fractions:

$5\frac{2}{18} - 2\frac{5}{18} = 0$

Now, subtract the fractions:

$\frac{10}{18} - \frac{10}{18} = 0$

Since both fractions cancel out, we have:

$0 = 0$

Now, you have two solutions for $x$:

1. $x = -5\frac{5}{17}$
2. $0 = 0$

So, the equation $(5\frac{5}{17}+x) \cdot (5\frac{1}{9}-2\frac{5}{18})=0$ has two solutions:

1. $x = -5\frac{5}{17}$
2. This solution doesn't provide any information about $x$ since it's always true ($0 = 0$).