Question

(у-5)×4=28;. 3×а-7=14; (24+d)÷8=7​

Answer 1

Ответ:

а)(у-5)*4=28.

Раскрываем скобки.

4у-20=28.

Переносим "-20" в правую часть уравнения. "-20" становится "+20".

4у=28+20.

Выполняем добавление.

4у=48.

Ищем "у".

у=48:4.

Выполняем деление.

у=12.

б)3*а-7=14.

3а-7=14.

3а=14+7.

3а=21.

а=21:3.

а=7.

в)(24+д):8=7.

24+д=7*8.

24+д=56.

д=56-24.

д=32.

Answer 2

To solve these equations, we'll isolate the variables and find their values:

1. (у-5)×4 = 28

First, we'll isolate у:

у - 5 = 28 ÷ 4 у - 5 = 7

Now, add 5 to both sides of the equation:

у = 7 + 5 у = 12

So, у = 12.

2. 3×а - 7 = 14

First, we'll isolate а:

3а - 7 = 14

Now, add 7 to both sides of the equation:

3а = 14 + 7 3а = 21

Finally, divide both sides by 3 to find the value of а:

а = 21 ÷ 3 а = 7

So, а = 7.

3. (24 + d) ÷ 8 = 7

First, we'll isolate (24 + d):

24 + d = 7 × 8 24 + d = 56

Now, subtract 24 from both sides of the equation to find the value of d:

d = 56 - 24 d = 32

So, d = 32.