Question

(128+x)-48=28 248:(41-2*x)=8 18*(7*x+26)=1854 (5*x+1):16=6 21*(5*x+140=2499

Answer 1

Ответ:

1)-52; 2)5 3)11 4)19 5)-4,2

Пошаговое объяснение:

1) 128+х=28+48

х=76- 128

х=- 52

2) 41-2х=248:8

-2х=31-41

-2х=-10

х=5

3)7х+26=1854:18

7х=103-26

7х=77

х=11

4)5х+1=6*16

5х+1=96

5х=95

х=19

5)5х+140=2499:21

5х+140=119

5х=119-140

х=- 21:5

х=-4,2

Answer 2

Let's solve each equation step by step:

1. $128 + x - 48 = 28$

First, combine like terms on the left side:

$80 + x = 28$

Now, isolate $x$ by subtracting 80 from both sides:

$x = 28 - 80$

$x = -52$

2. $248 / (41 - 2x) = 8$

First, multiply both sides by $(41 - 2x)$ to isolate the denominator:

$248 = 8 \cdot (41 - 2x)$

Now, divide both sides by 8:

$31 = 41 - 2x$

Subtract 41 from both sides:

$-10 = -2x$

Finally, divide both sides by -2 to solve for $x$:

$x = (-10) / (-2)$

$x = 5$

3. $18(7x + 26) = 1854$

First, distribute 18 on the left side:

$126x + 468 = 1854$

Now, isolate $x$ by subtracting 468 from both sides:

$126x = 1854 - 468$

$126x = 1386$

Divide both sides by 126 to solve for $x$:

$x = 1386 / 126$

$x = 11$

4. $(5x + 1) / 16 = 6$

First, multiply both sides by 16 to isolate the numerator:

$5x + 1 = 6 \cdot 16$

$5x + 1 = 96$

Now, subtract 1 from both sides:

$5x = 96 - 1$

$5x = 95$

Finally, divide both sides by 5 to solve for $x$:

$x = 95 / 5$

$x = 19$

5. $21(5x + 140) = 2499$

First, distribute 21 on the left side:

$105x + 2940 = 2499$

Now, isolate $x$ by subtracting 2940 from both sides:

$105x = 2499 - 2940$

$105x = -441$

Divide both sides by 105 to solve for $x$:

$x = (-441) / 105$

$x = -4.2$

So, the solutions to the equations are:

1. $x = -52$
2. $x = 5$
3. $x = 11$
4. $x = 19$
5. $x = -4.2$