Question

А) 2а-(7-2а)=Б) - 2а-2(-а+7)+14В)3(-2х-4)+2(3х+8)+2х​

Answer 1

Ответ:

а) 2а-(7-2а)=2а-7+2а=2а-7

б)-2а-2(-а+7)+14=-2а+2а-14+14=0

в)3*(-2х-4+2(3х+8))+2х=3(-2х-4+6х+16))+2х=3(4х+14)+2х=12х+42+2х=

=14х+42

Пошаговое объяснение: должно быть правильно

Answer 2

Let's solve each equation step by step:

A) 2a - (7 - 2a)

First, we can simplify the parentheses by distributing the negative sign: 2a - 7 + 2a

Next, we combine like terms: 4a - 7

So, the solution to equation A is 4a - 7.

B) -2a - 2(-a + 7) + 14

First, we simplify the parentheses by distributing the -2: -2a + 2a - 14 + 14

Next, we combine like terms: 0

Therefore, the solution to equation B is 0.

C) 3(-2x - 4) + 2(3x + 8) + 2x

First, we apply the distributive property within each parentheses: -6x - 12 + 6x + 16 + 2x

Next, we combine like terms: -6x + 6x + 2x - 12 + 16

The x-terms cancel out, and the constants simplify: 2x + 4

So, the solution to equation C is 2x + 4.