Question

1) 100a2-81=10a+9(10a-9) ​

Answer 1

Ответ:

а=1

а=0

Пошаговое объяснение:

1) 100a²-81=10a+9(10a-9) ​

100а²-81=10а+90а-81

100а²-100а=0

корни уравнения 0 и 1

Answer 2

Ответ: 100*а^2-81-10*а-90*а+81=0 или 100*а*(а-1)=0 или а1=0, а2=1.

Пошаговое объяснение:

Answer 3

To solve the equation 100a^2 - 81 = 10a + 9(10a - 9), follow these steps:

1. First, simplify the equation by applying the distributive property on the right side:

100a^2 - 81 = 10a + 90a - 81

2. Combine like terms on the right side:

100a^2 - 81 = 100a - 81

3. Now, let's isolate all terms involving 'a' on one side of the equation and constants on the other side. To do this, subtract 100a and add 81 to both sides of the equation:

100a^2 - 100a = 0

4. Factor out the common factor of '100a' on the left side:

100a(a - 1) = 0

5. Now, we have a quadratic equation. To find the values of 'a,' set each factor equal to zero and solve for 'a':

a = 0 a - 1 = 0

For the second equation, add 1 to both sides:

a = 1

So, the solutions to the equation are:

a = 0 a = 1