Question

1) |x - 1,5= 4; 2) (3 - x)= 5;3) |2x - 3) = 0;4) (6 - 5x)= 0;5) |x +11+5 = 3;6) (x + 5) - 2 = 7.​

Answer 1

я точна не знаю проста у меня мала времени

Answer 2

It looks like you've provided a set of equations, and some of them are absolute value equations while others are regular linear equations. Let's solve each of them:

1. |x - 1.5| = 4:

To solve this equation, we'll consider both the positive and negative cases for the absolute value:

a) x - 1.5 = 4: Add 1.5 to both sides: x = 4 + 1.5 x = 5.5

b) -(x - 1.5) = 4: Remove the negative sign: x - 1.5 = -4 Add 1.5 to both sides: x = -4 + 1.5 x = -2.5

So, there are two solutions: x = 5.5 and x = -2.5.

2. 3 - x = 5:

Subtract 3 from both sides to isolate x: 3 - x = 5 -x = 5 - 3 -x = 2

Now, multiply both sides by -1 to solve for x: x = -2

3. |2x - 3| = 0:

The absolute value of any real number is non-negative, so the only possible solution to this equation is when the expression inside the absolute value is 0:

2x - 3 = 0 Add 3 to both sides: 2x = 3 Divide by 2: x = 3/2 or 1.5

4. 6 - 5x = 0:

Subtract 6 from both sides: -5x = -6

Now, divide by -5 to solve for x: x = (-6)/(-5) x = 6/5 or 1.2

5. |x + 11 + 5| = 3:

First, simplify the expression inside the absolute value: |x + 16| = 3

Now, consider both the positive and negative cases:

a) x + 16 = 3: Subtract 16 from both sides: x = 3 - 16 x = -13

b) -(x + 16) = 3: Remove the negative sign: x + 16 = -3 Subtract 16 from both sides: x = -3 - 16 x = -19

So, there are two solutions: x = -13 and x = -19.

6. (x + 5) - 2 = 7:

First, simplify the equation by combining like terms on the left side: x + 5 - 2 = 7

Now, isolate x by adding 2 to both sides: x + 3 = 7

Subtract 3 from both sides to solve for x: x = 7 - 3 x = 4

So, the solution to this equation is x = 4.