Question

1)20+2x>0=2)35-5x<0=​

Answer 1

Ответ:

1)x>-10 2)x>7

Пошаговое объяснение:

1)20+2х>0

2х>-20

x>-10

2)35-5x<0

-5x<-35

5x>35

x>7

Answer 2

Let's solve these inequalities step by step:

1. $20 + 2x > 0$

First, subtract 20 from both sides of the inequality:

$2x > -20$

Now, divide both sides by 2 to isolate $x$:

$x > -10$

So, the solution to the first inequality is $x > -10$.

2. $35 - 5x < 0$

First, subtract 35 from both sides of the inequality:

$-5x < -35$

Now, divide both sides by -5. When you divide by a negative number, remember to reverse the inequality sign:

$x > 7$

So, the solution to the second inequality is $x > 7$.