Question

|×+5|=0 -|-а|=-1m²+3=-133c(-c+6)(c-12)=0​

Answer 1

Ответ:

1)x+5=0 x=5

2)-1

3)Не прав

Answer 2

It looks like you've provided a set of mathematical expressions. Let's break them down one by one:

1. |x + 5| = 0: This equation involves the absolute value of (x + 5). The absolute value of any real number is always non-negative. So, the only way for |x + 5| to equal 0 is if the expression inside the absolute value bars, (x + 5), equals 0. Therefore, you can solve for x as follows:

   x + 5 = 0 x = -5

   So, the solution to this equation is x = -5.

2. -|-a| = -1m² + 3 = -133c(-c + 6)(c - 12) = 0: It seems like you've combined several equations or expressions into one. Let's break it down step by step:

   -|-a| = -1m² + 3: This part of the equation seems to involve the absolute value of -a. The absolute value of any real number is always non-negative, so -|-a| is equal to -a if a is positive and -(-a) = a if a is negative. Since the right side is a constant value (-1m² + 3), this equation simplifies to:

   -a = -1m² + 3

   Now, we need more information about what "m" represents to solve this equation further.

   = -133c(-c + 6)(c - 12) = 0: This part of the equation appears to be a polynomial equation. To solve it, we set each factor equal to zero and find the roots:

   -133c = 0 c = 0

   -c + 6 = 0 c = 6

   c - 12 = 0 c = 12

   So, the solutions to this part of the equation are c = 0, c = 6, and c = 12.

Please provide more information or clarify if there are any specific values for variables like "m" that are missing, or if you have further questions about these equations.