Question

34. 1)3x + (5x - 2) < 3 - 2 x,4(5x - 1) - 21x > 1 - 3x;​

Answer 1

Ответ:

3x + (5x - 2) < 3 - 2 x,

8х-2<3-2х

8х+2х<3+2

10х<5

х< 1/2

4(5x - 1) - 21x > 1 - 3x;​

20х-4-21х>1-3х

-х-4>1-3х

-х+3х>1+4

2х>5

х>5/2

Пошаговое объяснение:

Answer 2

To solve these inequalities, you'll want to isolate the variable x in each inequality. Let's go through each one step by step:

1. $3x + (5x - 2) < 3 - 2x$

First, distribute the -1 on the right side of the inequality:

$3x + 5x - 2 < 3 - 2x$

Combine like terms on both sides:

$8x - 2 < 3 - 2x$

Add 2x to both sides to isolate the x terms on the left side:

$8x + 2x - 2 < 3$

$10x - 2 < 3$

Now, add 2 to both sides:

$10x < 3 + 2$

$10x < 5$

Finally, divide both sides by 10 to solve for x:

$x < \frac{5}{10}$

$x < \frac{1}{2}$

So the solution for the first inequality is $x < \frac{1}{2}$.

2. $4(5x - 1) - 21x > 1 - 3x$

First, distribute the 4 on the left side of the inequality:

$20x - 4 - 21x > 1 - 3x$

Combine like terms on both sides:

$-x - 4 > 1 - 3x$

Now, add 3x to both sides to isolate the x terms on the right side:

$-x + 3x - 4 > 1$

$2x - 4 > 1$

Next, add 4 to both sides:

$2x - 4 + 4 > 1 + 4$

$2x > 5$

Finally, divide both sides by 2 to solve for x:

$x > \frac{5}{2}$

So the solution for the second inequality is $x > \frac{5}{2}$.

In summary:

1. $x < \frac{1}{2}$
2. $x > \frac{5}{2}$