Question

4) { 2 (3х + 2) > 5 (x-1). 7 (x+2) < 3 (2x +3)

Answer 1

2x-8<0

-3x<-6

x<4

x>2

Ответ : [2;4]Ответ:

Пошаговое объяснение:

Answer 2

To solve the given system of inequalities, let's start by simplifying each inequality:

1. $2(3x + 2) > 5(x - 1)$ Expanding both sides: $6x + 4 > 5x - 5$

Subtract $5x$ from both sides: $6x - 5x + 4 > -5$

Simplify: $x + 4 > -5$

Subtract 4 from both sides: $x > -9$

So, the first inequality simplifies to $x > -9$.

2. $7(x + 2) < 3(2x + 3)$ Expanding both sides: $7x + 14 < 6x + 9$

Subtract $6x$ from both sides: $7x - 6x + 14 < 9$

Simplify: $x + 14 < 9$

Subtract 14 from both sides: $x < -5$

So, the second inequality simplifies to $x < -5$.

Putting both inequalities together, the solution for the given system of inequalities is $-9 < x < -5$.