Question

2•|x-4|=6 12•|2x-5|=-60 2•(3x-5) →2x+10

Answer 1

Ответ:

2•|x-4|=6

|x-4|=3

x-4=3        x-4=-3

x=7            x=1

12•|2x-5|=-60

|2x-5|=-5

нет решения

2•(3x-5)=2x+10

6x-10=2x+10

4x=20

x=5

Answer 2

It seems like you've provided a set of equations and expressions. Let's break them down one by one.

1. $2 \cdot |x-4| = 6$:

   To solve this equation, we'll first isolate the absolute value:

   $|x-4| = 3$

   This means that either $x-4 = 3$ or $x-4 = -3$.

   Solving these separately:

   $x-4 = 3$ gives $x = 7$.

   $x-4 = -3$ gives $x = 1$.

   So, the solutions are $x = 1$ and $x = 7$.

2. $12 \cdot |2x-5| = -60$:

   The absolute value of any real number is non-negative, so it's not possible for $|2x-5|$ to be negative. Therefore, there are no real solutions for this equation.

3. $2 \cdot (3x-5)$:

   This is an expression, not an equation. If you want to simplify it, you've already done so correctly:

   $2 \cdot (3x-5) = 6x - 10$.

Please double-check the second equation, as it seems there might be a mistake in the provided values. If you meant a different equation, please provide the correct one.