Question

26. 1) (3y - 7): 5 = 33 : 15;​

Answer 1

Ответ:

$(3y - 7) \div 5 = 33 \div 15 \\ 15(3y - 7) = 165 \\ 3y - 7 = 11 \\ 3y = 11 + 7 \\ 3y = 18 \\ y = 18 \div 3 \\ y = 6$

Answer 2

To solve the equation (3y - 7) / 5 = 33 / 15, you can follow these steps:

1. First, simplify the right side of the equation: 33 / 15 = 11 / 5

2. Now, you have the equation: (3y - 7) / 5 = 11 / 5

3. To get rid of the fractions, you can multiply both sides of the equation by 5: 5 * [(3y - 7) / 5] = 5 * (11 / 5)

4. The 5s on the left side cancel out, leaving you with: 3y - 7 = 11

5. Now, isolate the variable y by adding 7 to both sides of the equation: 3y - 7 + 7 = 11 + 7

6. Simplify further: 3y = 18

7. Finally, divide both sides by 3 to solve for y: (3y) / 3 = 18 / 3 y = 6

So, the solution to the equation (3y - 7) / 5 = 33 / 15 is y = 6.