Question

8x-(2x-9)=4x-(8+4x),4-2y-(5-3y)=y-1-(y-8),3x+1+(5x+8)=33+(x+11)

Answer 1

Ответ:

$8x - (2x - 9) = 4x - (8 + 4x) \\ 8x - 2x + 9 = 4x - 8 - 4x \\ 6x = - 8 - 9 \\ 6x = - 17 \\ x = - \frac{17}{6}$

$4 - 2y - (5 -y) = y - 1 - (y - 8) \\ 4 - 2y - 5 + y = y - 1 - y + 8 \\ - y = 7 + 1 \\ - y = 8 \\ y = - 8$

$3x + 1 + (5x + 8) = 33 + (x + 11) \\ 3x + 1 + 5x + 8 = 33 + x + 11 \\ 8x - x = 44 - 9 \\ 7x = 35 \\ x = 5$

Answer 2

Let's solve each equation step by step:

1. $8x - (2x - 9) = 4x - (8 + 4x)$

First, distribute the negative sign inside the parentheses:

$8x - 2x + 9 = 4x - 8 - 4x$

Combine like terms:

$6x + 9 = -8$

Now, isolate $x$ by moving the constants to the right side:

$6x = -8 - 9$

$6x = -17$

Now, divide both sides by 6 to solve for $x$:

$x = -\frac{17}{6}$

2. $4 - 2y - (5 - 3y) = y - 1 - (y - 8)$

First, distribute the negative sign inside the parentheses:

$4 - 2y - 5 + 3y = y - 1 - y + 8$

Combine like terms:

$-2y - 1 = 7$

Now, isolate $y$ by moving the constants to the right side:

$-2y = 7 + 1$

$-2y = 8$

Now, divide both sides by -2 to solve for $y$:

$y = -4$

3. $3x + 1 + (5x + 8) = 33 + (x + 11)$

First, distribute the parentheses on both sides:

$3x + 1 + 5x + 8 = 33 + x + 11$

Combine like terms:

$8x + 9 = 44 + x$

Now, isolate $x$ by moving the constants to the right side:

$8x = 44 + x - 9$

$8x = 35 + x$

Now, subtract $x$ from both sides to solve for $x$:

$7x = 35$

Now, divide both sides by 7 to find $x$:

$x = 5$