Question

1) 10a +(4-4a) 2) -(4b-10)+(4-5b) 3) (c-5d)-(-d+5c) 4) -(5n+m)+(-4n+8m)-(2m-5n)

Answer 1

Ответ:

Пошаговое объяснение:

1) 10a +(4-4a) = 10а + 4 - 4а = 6а + 4

2) -(4b-10)+(4-5b) = -4b + 10 + 4 - 5b = 14 - 9b

3) (c-5d)-(-d+5c) = c - 5d + d -5c = - 4d - 4c

4) -(5n+m)+(-4n+8m)-(2m-5n)= -5n -m - 4n +8m - 2m +5n = 5m - 4n

Answer 2

Let's simplify each of the given expressions:

1. 10a + (4 - 4a) = 10a + 4 - 4a (Distribute the negative sign inside the parentheses) = (10a - 4a) + 4 (Combine like terms) = 6a + 4

2. -(4b - 10) + (4 - 5b) = -4b + 10 + 4 - 5b (Distribute the negative sign inside the first set of parentheses) = (-4b - 5b) + (10 + 4) (Combine like terms) = -9b + 14

3. (c - 5d) - (-d + 5c) = c - 5d + d - 5c (Distribute the negative sign inside the second set of parentheses) = (c - 5c) + (-5d + d) (Combine like terms) = -4c - 4d

4. -(5n + m) + (-4n + 8m) - (2m - 5n) = -5n - m - 4n + 8m - 2m + 5n (Distribute the negative sign inside each set of parentheses) = (-5n + 5n - 4n) + (-m + 8m - 2m) (Combine like terms) = 0n + 2m - m = 2m - m = m

So, the simplified expressions are:

1. 6a + 4
2. -9b + 14
3. -4c - 4d
4. m