Question

X²-6x+8=0 D=? X¹=? X²=?

Answer 1

X^2-6X+8=0
D=6^2-4*8=4
x1=(6+2):2=4
x2=(6-2):2=2
Ответ:4 и 2

Answer 2

In the quadratic equation $x^2 - 6x + 8 = 0$, you can use the quadratic formula to find the solutions for $x$, where $a = 1$, $b = -6$, and $c = 8$.

The quadratic formula is given by:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In this case:

$a = 1$ $b = -6$ $c = 8$

Now, plug these values into the quadratic formula:

$x = \frac{-(-6) \pm \sqrt{(-6)^2 - 4(1)(8)}}{2(1)}$

Simplify it further:

$x = \frac{6 \pm \sqrt{36 - 32}}{2}$ $x = \frac{6 \pm \sqrt{4}}{2}$ $x = \frac{6 \pm 2}{2}$

Now, you can calculate the two possible solutions:

1. $x_1 = \frac{6 + 2}{2} = \frac{8}{2} = 4$
2. $x_2 = \frac{6 - 2}{2} = \frac{4}{2} = 2$

So, the solutions for $x$ are:

$x_1 = 4$ and $x_2 = 2$.