Question

7у=20+2у,32х-5=19+20х​

Answer 1

Ответ:

Пошаговое объяснение:

7у=20+2у

5у = 20

у= 20 :5

у= 4

32х-5=19+20х​

12х= 24

х= 24:12

х= 2

Answer 2

To solve these equations for у and х, we'll isolate the variables on one side of the equations. Let's start with the first equation:

1. 7у = 20 + 2у

To isolate у, you can subtract 2у from both sides of the equation:

7у - 2у = 20

This simplifies to:

5у = 20

Now, divide both sides by 5 to solve for у:

5у/5 = 20/5

y = 4

So, у = 4.

Now, let's move on to the second equation:

2. 32х - 5 = 19 + 20х

To isolate х, you can move all terms containing х to one side and constants to the other side of the equation. Start by subtracting 20х from both sides:

32х - 20х - 5 = 19

Now, combine like terms on the left side:

12х - 5 = 19

Next, add 5 to both sides to get rid of the -5 on the left side:

12х - 5 + 5 = 19 + 5

This simplifies to:

12х = 24

Now, divide both sides by 12 to solve for х:

12х/12 = 24/12

x = 2

So, х = 2.

The solutions to the equations are: у = 4 х = 2