Question

S1=93кмt1=1.5часS2=142кмt2=2.5часV=?​

Answer 1

Ответ:

S1=93км

t1=1.5час

S2=142км

t2=2.5час

V=93+147=240

1.5+2.5=4

240:4=60км/час

V=60км/час

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Answer 2

To find the average velocity (V), you can use the following formula:

$V = \frac{S}{t}$

Where:

• $S$ is the total distance traveled.
• $t$ is the total time taken.

In your case, you have two segments with different distances and times. You need to calculate the average velocity for each segment and then find the total average velocity for the entire trip.

For the first segment (S1 = 93 km, t1 = 1.5 hours):

$V_1 = \frac{S_1}{t_1} = \frac{93\, \text{km}}{1.5\, \text{hours}} = 62\, \text{km/h}$

For the second segment (S2 = 142 km, t2 = 2.5 hours):

$V_2 = \frac{S_2}{t_2} = \frac{142\, \text{km}}{2.5\, \text{hours}} = 56.8\, \text{km/h}$

Now, to find the total average velocity (V) for the entire trip, you can use the concept of weighted averages. You'll weigh each segment's velocity by the distance it covers and then sum them up:

$V = \frac{S_1 \cdot V_1 + S_2 \cdot V_2}{S_1 + S_2}$

Plug in the values:

$V = \frac{(93\, \text{km} \cdot 62\, \text{km/h}) + (142\, \text{km} \cdot 56.8\, \text{km/h})}{93\, \text{km} + 142\, \text{km}}$

Now, calculate the total average velocity (V):

$V = \frac{5766\, \text{km} \cdot \text{km/h} + 8086.4\, \text{km} \cdot \text{km/h}}{235\, \text{km}}$

$V = \frac{13852.4\, \text{km} \cdot \text{km/h}}{235\, \text{km}}$

Now, divide to find the total average velocity (V):

$V \approx 59\, \text{km/h}$

So, the total average velocity for the entire trip is approximately 59 kilometers per hour.