Question

(13 x + 4y + 17 = 0,12 x - 3y + 9 = 0.​

Answer 1

Ответ:

13 x + 4y + 17 = 0,

12 x - 3y + 9 = 0.

Answer 2

You have provided two linear equations:

1. 13x + 4y + 17 = 0
2. 12x - 3y + 9 = 0

You can solve this system of equations to find the values of x and y that satisfy both equations. Here's how you can do it:

First, you can isolate one of the variables in one of the equations. Let's isolate x in the second equation (equation 2):

12x - 3y + 9 = 0

Subtract 9 from both sides:

12x - 3y = -9

Now, divide both sides by 12 to solve for x:

x = (-9 + 3y) / 12

Now, you have an expression for x in terms of y.

Next, substitute this expression for x into the first equation (equation 1):

13x + 4y + 17 = 0

13[(-9 + 3y) / 12] + 4y + 17 = 0

Now, simplify and solve for y:

(13/12)(-9 + 3y) + 4y + 17 = 0

Multiply both sides by 12 to get rid of the fraction:

13(-9 + 3y) + 48y + 204 = 0

Now, distribute and simplify:

-117 + 39y + 48y + 204 = 0

Combine like terms:

87y + 87 = 0

Subtract 87 from both sides:

87y = -87

Now, divide by 87 to solve for y:

y = -87 / 87

y = -1

Now that you have found the value of y, you can substitute it back into the expression for x:

x = (-9 + 3y) / 12 x = (-9 + 3(-1)) / 12 x = (-9 - 3) / 12 x = -12 / 12 x = -1

So, the solution to the system of equations is:

x = -1 y = -1