Question

(3/4 +4 3/5 * 9/56):2/3/=

Answer 1

...= (3/4+23/5×9/56)×3/2= (3/4+207/280)×3/2= 417/280 × 3/2= 1251/560 = 2 131/560≈ 2,233

Answer 2

To solve this expression, you should follow the order of operations (PEMDAS/BODMAS), which stands for Parentheses/Brackets, Exponents/Orders (i.e., powers and square roots, etc.), Multiplication and Division (left-to-right), and Addition and Subtraction (left-to-right).

1. First, simplify the multiplication: (4 3/5 * 9/56) = (23/5 * 9/56)

2. Now, multiply the fractions: (23/5 * 9/56) = (207/280)

3. Next, add 3/4 and the result from the previous step: (3/4 + 207/280) = (105/140 + 207/280)

4. Find a common denominator for the fractions, which is 280: (105/140 + 207/280) = (105 * 2/140 * 2 + 207/280) = (210/280 + 207/280)

5. Now, add the fractions: (210/280 + 207/280) = (417/280)

6. Finally, divide the result by 2/3: (417/280) ÷ (2/3) = (417/280) * (3/2)

7. Multiply the fractions: (417/280) * (3/2) = (417 * 3) / (280 * 2) = 1251/560

So, the final result is 1251/560.