Question

2) [3(x + 2y) - y - 27 = 0,14(x + y) - 3x – 23 = 0;​

Answer 1

Ответ:

3(x + 2y) - y - 27 = 0

4(x + y) - 3x - 23 = 0

3x + 6y - y = 27

4x + 4y - 3x = 23

3x + 5y = 27

x + 4y = 23

3x + 5y = 27

x = 23 - 4y

69 - 12y + 5y = 27

x = 23 - 4y

-7y = -42

x = 23 - 4y

y = 6

x = -1

Ответ: y = 6, x = -1

Пошаговое объяснение:

Answer 2

To solve this system of linear equations:

1. 3(x + 2y) - y - 27 = 0
2. 14(x + y) - 3x - 23 = 0

You can use the method of your choice, such as substitution or elimination. I'll demonstrate the elimination method:

Step 1: Distribute the constants on the left side of the equations:

1. 3x + 6y - y - 27 = 0
2. 14x + 14y - 3x - 23 = 0

Step 2: Combine like terms in each equation:

1. 3x + 5y - 27 = 0
2. 11x + 14y - 23 = 0

Step 3: Isolate one of the variables in one of the equations. Let's solve the first equation for x:

3x = 27 - 5y x = (27 - 5y) / 3

Step 4: Substitute the expression for x in terms of y into the second equation:

11((27 - 5y) / 3) + 14y - 23 = 0

Now, solve for y:

11(27 - 5y) + 42y - 69 = 0 297 - 55y + 42y - 69 = 0

Combine like terms:

-13y + 228 = 0

Subtract 228 from both sides:

-13y = -228

Divide by -13:

y = 228 / 13 y ≈ 17.54

Step 5: Now that we have the value of y, substitute it back into the expression for x:

x = (27 - 5y) / 3 x = (27 - 5(17.54)) / 3 x ≈ 2.82

So, the solution to the system of equations is approximately x ≈ 2.82 and y ≈ 17.54.