Question

– 2х + y = 4,х+ Зу = 5.​

Answer 1

Ответ:

1.2х+у=4

2х+у-4=4-4

2х+у-4=0

Пошаговое объяснение:

2.х+3у=5

Х+3у-5=5-5

Х+3у-5=0

Answer 2

Ответ:

В объяснении.

Пошаговое объяснение:

-2х+у=4

(-2;0)→ -2*(-2)+0=4+0=4. Верно.

х+3у=5

(2;1)→2+3*1=2+3=5. Верно.

Answer 3

It seems like you've provided a system of two linear equations. To find the solution to this system, you can use either the substitution method or the elimination method. Let's use the elimination method to solve this system of equations:

The system is:

1. -2x + y = 4
2. x + 2y = 5

First, let's make the coefficients of one of the variables equal. In this case, let's try to eliminate x. To do that, we'll multiply the second equation by 2 so that the coefficients of x in both equations will cancel out when we add the equations together.

So, multiply equation 2 by 2: 2(x + 2y) = 2(5) 2x + 4y = 10

Now the system becomes:

1. -2x + y = 4
2. 2x + 4y = 10

Now, add the two equations together to eliminate x:

(-2x + y) + (2x + 4y) = 4 + 10

This simplifies to:

5y = 14

Now, isolate y by dividing both sides by 5:

y = 14/5

Now that we have the value of y, we can substitute it back into either of the original equations to solve for x. Let's use equation 1:

-2x + (14/5) = 4

Now, solve for x:

-2x = 4 - 14/5

-2x = (20/5) - (14/5)

-2x = (6/5)

Now, divide by -2 to isolate x:

x = (6/5) / (-2)

x = (6/5) * (-1/2)

x = -3/5

So, the solution to the system of equations is:

x = -3/5 y = 14/5