Question

1/8(16х-8) -1/9(9х-36) =8 2,3(4х-1) -3,5(2х-3) =+8, 2

Answer 1

в другому прикладі х дорівнює 9.54

думаю зрозуміло

Answer 2

To solve these equations, we'll start by simplifying and then isolating the variable $x$.

Equation 1: $\frac{1}{8}(16x-8) - \frac{1}{9}(9x-36) = 8$

First, simplify each term by distributing the fractions:

$\frac{1}{8} * 16x - \frac{1}{8} * 8 - \frac{1}{9} * 9x + \frac{1}{9} * 36 = 8$

Now, simplify each term:

$2x - 1 - x + 4 = 8$

Combine like terms:

$x + 3 = 8$

Now, isolate $x$ by subtracting 3 from both sides:

$x = 8 - 3$

$x = 5$

So, the solution to the first equation is $x = 5$.

Now, let's solve the second equation:

Equation 2: $2.3(4x-1) - 3.5(2x-3) = 8.2$

First, distribute the coefficients:

$9.2x - 2.3 - 7x + 10.5 = 8.2$

Now, simplify each term:

$9.2x - 7x - 2.3 + 10.5 = 8.2$

Combine like terms:

$2.2x + 8.2 = 8.2$

Now, isolate $x$ by subtracting 8.2 from both sides:

$2.2x = 8.2 - 8.2$

$2.2x = 0$

Now, divide both sides by 2.2 to find $x$:

$x = \frac{0}{2.2}$

$x = 0$

So, the solution to the second equation is $x = 0$.