Question

2) 6x+ y=17 [4x+3y= 23.​

Answer 1

Ответ:

{6x+y=17

{4x+3y=23

{y=17-6x

{4x+3y=23

4x+3(17-6x)=23

4x+51-18x=23

4x-18x=23-51

-14x=-28

x=-28÷-14

x=2

y=17-6×2

y=5

ответ:

(x;y)=(2;5)

Answer 2

To solve this system of equations:

1. 6x + y = 17
2. 4x + 3y = 23

You can use either the substitution method or the elimination method. I'll show you how to solve it using the elimination method:

First, multiply both sides of equation (1) by 3 to make the coefficients of y in both equations equal:

1. 18x + 3y = 51

Now, subtract equation (2) from this new equation to eliminate the variable y:

(18x + 3y) - (4x + 3y) = 51 - 23

This simplifies to:

14x = 28

Now, divide both sides by 14 to solve for x:

x = 28 / 14 x = 2

Now that you have the value of x, you can substitute it back into either equation (1) or (2). Let's use equation (1):

6x + y = 17 6(2) + y = 17 12 + y = 17

Now, subtract 12 from both sides to solve for y:

y = 17 - 12 y = 5

So, the solution to the system of equations is x = 2 and y = 5.