Вопрос задан 22.06.2023 в 12:04. Предмет Математика. Спрашивает Ковязин Кирилл.

Реши систему уравнений {4x+2y=20 9x-3y=30

Смотреть ответ пж быстрее Asem070396 Asem070396 Ответ: { 4х+2у=20 / *3 { 9х-3у=30 / *2 {12х+[6у]=60. [6у (+ -) сокращается { 18х-[6у]=60 {12х=60. Их плюсуем {18х=60 12х+18х=60+60 30х=120 Х=4 4*4+2у=20 16+2у=20 2у=4 У=2 Пошаговое объяснение: в рисунке есть подробно Новые вопросы в Математика Зделайте пожалуйста без скама От класса нужны два представителя в школьный совет. Мальчик и девочка. Посчитайте, сколько есть возможностей выбрать представителей, если в классе:а) … 15 девочек и 12 мальчиков с) 18 мальчиков, которые составляют 60% всех учеников класса ​ помогите решить уравнение срочно Решите факториалы 1) 8!*8!*7!*9! / 0!*8!*7!*1!*16! 2) 8!*8!*9!*7!/ 6!*2!*1!*7!*16! Протягом звітного місяця громадянин Коваленко одержав дохід у вигляді заробітної плати у розмірі 12000 грн. та лікарняні за дні хвороби у сумі 2800 г … рн. Розрахуйте суму ПДФО та військового збору, що підлягає утриманню з доходів громадянина, та суму отриманого доходу після оподаткування. 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Давайте рассмотрим вашу систему уравнений и найдем ее решение:

У вас есть два уравнения:

  1. 4x + 2y = 20
  2. 9x - 3y = 30

Давайте решим ее по методу умножения или деления уравнений, чтобы избавиться от одной из переменных. Выберем второе уравнение и умножим его на 2, чтобы избавиться от коэффициента y:

Умножим второе уравнение на 2:

2(9x - 3y) = 2 * 30 18x - 6y = 60

Теперь у нас есть система из двух уравнений:

  1. 4x + 2y = 20
  2. 18x - 6y = 60

Теперь сложим оба уравнения, чтобы избавиться от переменной y:

(4x + 2y) + (18x - 6y) = 20 + 60

Сгруппируем переменные x и y:

4x + 18x + 2y - 6y = 80

Сложим коэффициенты при x и y:

22x - 4y = 80

Теперь у нас есть уравнение с одной переменной x:

22x - 4y = 80

Теперь, разделим обе стороны на 2:

(22x - 4y) / 2 = 80 / 2 11x - 2y = 40

Теперь у нас есть система из двух уравнений:

  1. 4x + 2y = 20
  2. 11x - 2y = 40

Теперь сложим оба уравнения:

(4x + 2y) + (11x - 2y) = 20 + 40

Сгруппируем переменные x и y:

4x + 11x + 2y - 2y = 60

Сложим коэффициенты при x и y:

15x = 60

Теперь разделим обе стороны на 15, чтобы найти значение x:

(15x) / 15 = 60 / 15 x = 4

Теперь, когда у нас есть значение x, мы можем найти значение y, подставив его в любое из исходных уравнений. Давайте подставим его в первое уравнение:

4x + 2y = 20 4 * 4 + 2y = 20 16 + 2y = 20

Выразим y:

2y = 20 - 16 2y = 4

Теперь разделим обе стороны на 2:

(2y) / 2 = 4 / 2 y = 2

Итак, решение вашей системы уравнений:

x = 4 y = 2

Ответ: {x = 4, y = 2}

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