Question

3x +y =16,4x - 3y =17​

Answer 1

Ответ:(5;3)

Пошаговое объяснение:

9x+3y=48

4x-3y=17

————-/

13x=65

X=5

——————

4 • 5 -3y= 17

20 - 3y =17

—————-

-3y= 17-20

-3y = -3

Y = 1

Answer 2

Ответ:

x=5 y=1

Пошаговое объяснение:

3x +y =16,

4x - 3y =17

y = 16 - 3x

4x - 3(16-3x) = 17

y = 16 - 3x

4x - 48 + 9x = 17

y = 16 - 3x

13x = 17 + 48

13x = 65

x = 65/13 = 5

x = 5

y = 16 - 3x = 16 - 3*5 = 1

y = 1

Answer 3

To solve this system of equations, you can use either the substitution method or the elimination method. I will use the elimination method here.

Given the equations:

1. $3x + y = 16$
2. $4x - 3y = 17$

First, let's multiply equation 1 by 3 so that the coefficients of $y$ in both equations will cancel each other out when added:

$3(3x + y) = 3(16)$ $9x + 3y = 48$

Now, your equations are:

1. $9x + 3y = 48$
2. $4x - 3y = 17$

Add equation 1 and equation 2 to eliminate $y$:

$(9x + 3y) + (4x - 3y) = 48 + 17$ $13x = 65$

Now, divide by 13 to solve for $x$:

$x = 5$

Now that you have the value for $x$, substitute it back into equation 1 to solve for $y$:

$3x + y = 16$ $3(5) + y = 16$ $15 + y = 16$

Subtract 15 from both sides:

$y = 1$

Therefore, the solution to the system of equations is $x = 5$ and $y = 1$.