Question

Sin x =3/4 Знайты cos x

Answer 1

Пошаговое объяснение:

надеюсь что это правильный ответ

Answer 2

To find the value of cos(x) when sin(x) = 3/4, you can use the identity:

$\sin^2(x) + \cos^2(x) = 1$

Since we already know that sin(x) = 3/4, we can substitute it into the equation and solve for cos(x):

$\left(\frac{3}{4}\right)^2 + \cos^2(x) = 1$

$\frac{9}{16} + \cos^2(x) = 1$

$\cos^2(x) = 1 - \frac{9}{16}$

$\cos^2(x) = \frac{16}{16} - \frac{9}{16}$

$\cos^2(x) = \frac{7}{16}$

Taking the square root of both sides, we get:

$\cos(x) = \pm \sqrt{\frac{7}{16}}$

However, since sin(x) is positive, x must be in the first or second quadrant where cos(x) is also positive. Hence, the solution is:

$\cos(x) = \sqrt{\frac{7}{16}} = \frac{\sqrt{7}}{4}$