Question

-1/16-(-1/4)= 2/7-x=3/14 1/5-(-7/15)-41/45= 1/3+(-2/9)+4/27+(-8/81)=

Answer 1

Ответ:

$1)\ \ -\dfrac{1}{16}-(-\dfrac{1}{4})=-\dfrac{1}{16}+\dfrac{1}{4}=\dfrac{-1+4}{16}=\dfrac{3}{16}\\\\\\2)\ \ \dfrac{2}{7}-x=\dfrac{3}{14}\ \ ,\ \ x=\dfrac{2}{7}-\dfrac{3}{14}\ \ ,\ \ x=\dfrac{1}{14}$

$3)\ \ \dfrac{1}{5}-(-\dfrac{7}{15})-\dfrac{41}{45}=\dfrac{9+7\cdot 3-41}{45}=-\dfrac{11}{45}\\\\\\4)\ \ \dfrac{1}{3}-\dfrac{2}{9}+\dfrac{4}{27}-\dfrac{8}{81}=\dfrac{27-2\cdot 9+4\cdot 3-8}{81}=\dfrac{13}{81}$

Answer 2

Ответ:

Пошаговое объяснение:

Answer 3

Let's solve each of these equations step by step:

1. -1/16 - (-1/4) = First, simplify the double negative by changing the subtraction into addition: -1/16 + 1/4 To add these fractions, you need a common denominator, which is 16 in this case. Convert 1/4 into a fraction with a denominator of 16 by multiplying both the numerator and denominator by 4: -1/16 + 4/16 Now, you can add them: (-1 + 4)/16 = 3/16

2. 2/7 - x = 3/14 To isolate x, you can subtract 2/7 from both sides of the equation: 2/7 - 2/7 - x = 3/14 - 2/7 -x = (3/14) - (4/14) -x = -1/14 To get x by itself, multiply both sides by -1: x = 1/14

3. 1/5 - (-7/15) - 41/45 = First, simplify the double negative: 1/5 + 7/15 - 41/45 To add these fractions, you need a common denominator, which is 45 in this case. Convert 1/5 into a fraction with a denominator of 45 by multiplying both the numerator and denominator by 9: (9/45) + 7/15 - 41/45 Now, you can add them: (9/45 + 7/15 - 41/45) (-32/45) + 7/15 To add these fractions, you need a common denominator, which is 45: (-32/45) + (21/45) (-32 + 21)/45 = -11/45

4. 1/3 + (-2/9) + 4/27 + (-8/81) = Simply add the fractions: (1/3) + (-2/9) + (4/27) + (-8/81) To add these fractions, you need a common denominator, which is 81 in this case: (27/81) + (-18/81) + (4/27) + (-8/81) Now, add them: (27 - 18 + 4 - 8)/81 (5 - 26)/81 (-21/81) To simplify further, you can divide both the numerator and denominator by their greatest common divisor, which is 3: (-7/27)