Question

A²-6a-8b+b²=25a+b=?​

Answer 1

Ответ:       a + b = 7 .      

Пошаговое объяснение:

a²- 6a - 8b + b² = - 25 ;

( a² - 2*a *3 + 3² ) - 3² + ( b² - 2*b* 4 + 4² ) - 4² = - 25 ;

( a - 3 )² + ( b - 4 )² = 0 ;

a - 3 = 0 ;      i      b - 4 = 0 ;

     a = 3 ;                  b = 4 .          a + b = 3 + 4 = 7 .

Answer 2

To find the value of "25a + b" given the equation:

a² - 6a - 8b + b² = 25

We can rearrange the equation to isolate "25a + b":

a² - 6a - 8b + b² = 25

First, let's group the terms with 'a' and the terms with 'b':

(a² - 6a) + (-8b + b²) = 25

Now, complete the square for both the 'a' and 'b' terms by adding and subtracting the appropriate constants. For 'a,' we'll add (6/2)² = 9, and for 'b,' we'll add (8/2)² = 16:

(a² - 6a + 9 - 9) + (-8b + b² + 16 - 16) = 25

Now, factor the perfect square trinomials:

(a - 3)² - 9 + (b - 4)² - 16 = 25

Now, simplify the equation:

(a - 3)² + (b - 4)² = 25 + 9 + 16 (a - 3)² + (b - 4)² = 50

So, you have:

(a - 3)² + (b - 4)² = 50

Now, you can't directly find the value of 25a + b with this information because the equation involves squares. If you have more information or constraints on 'a' and 'b,' you might be able to find specific values for them and subsequently calculate 25a + b.