Question

2×(28÷7)÷6+39-19(6×3)×(27÷9)-14×3

Answer 1

2 · (28 : 7) : 6 + 39 - 19 · (6 · 3) · (27 : 9) - 14 · 3 = -1027 2/3

1) 28 : 7 = 4

2) 6 · 3 = 18

3) 27 : 9 = 3

4) 2 · 4 = 8

5) 8 : 6 = 8/6 = 4/3 = 1 целая 1/3

6)  19 · 18 = 342

7) 342 · 3 = 1026

8) 14 · 3 = 42

9) 1 целая 1/3 + 39 = 40 целых 1/3

10) 40 1/3 - 1026 = - (1025 3/3 - 40 1/3) = -985 целых 2/3

11) -985 2/3 - 42 = -1027 целых 2/3

Ответ: -1027,(6).

Answer 2

To solve this expression step by step, follow the order of operations (PEMDAS/BODMAS):

1. Simplify within the parentheses and perform any divisions: 2×(28÷7)÷6+39-19(6×3)×(27÷9)-14×3 = 2×(4)÷6 + 39 - 19(18)×(3) - 14×3

2. Perform the multiplications and divisions in order from left to right: = 8÷6 + 39 - 342 - 42

3. Simplify the additions and subtractions in order from left to right: = 1.333 + 39 - 342 - 42 = 1.333 - 303 = -301.667

Therefore, 2×(28÷7)÷6+39-19(6×3)×(27÷9)-14×3 is approximately equal to -301.667.