Question

В двух корзинах было 15 мячей. Когда из одной корзины детей достали 2 шарика, а к другому приложили 3 шарика, вот и получилось в корзинах столько же мячей. Сколько мячей было в каждой корзине в начале?​

Answer 1

Ответ:

10 и 5

Пошаговое объяснение:

10-3=7, 5+2=7

Answer 2

Problem Analysis

We are given that there were 15 balls in two baskets. After removing 2 balls from one basket and adding 3 balls to the other basket, the total number of balls in both baskets remained the same. We need to determine the initial number of balls in each basket.

Solution

Let's assume the number of balls in the first basket is x and the number of balls in the second basket is y.

According to the given information, we have the following equations:

1. x + y = 15 (equation 1) 2. (x - 2) + (y + 3) = 15 (equation 2)

We can solve these equations to find the values of x and y.

Solving the Equations

Let's solve the equations using the substitution method.

From equation 1, we have x = 15 - y.

Substituting this value of x into equation 2, we get:

(15 - y - 2) + (y + 3) = 15

Simplifying the equation:

13 - y + y + 3 = 15

Combining like terms:

16 - y = 15

Adding y to both sides:

16 = 15 + y

Subtracting 15 from both sides:

1 = y

Now, substituting the value of y back into equation 1, we get:

x + 1 = 15

Subtracting 1 from both sides:

x = 14

Answer

Therefore, there were 14 balls in the first basket and 1 ball in the second basket initially.