Question

Из Москвы на юг одновременно вылетели две стаи птиц. В первой стае были птицы помельче и они летели со скоростью 50 км/ч. Вторая стая состояла из уток и летела со скоростью 60 км/ч. Утки прилетели в место зимовки на 4 часа раньше первой стаи. Какое расстояние между Москвой и местом зимовки птиц?

Answer 1

Ответ: 40км

Пошаговое объяснение:

60-50=10км/час скорость уток больше

10×4=40км

Answer 2

Problem Analysis

We are given that two flocks of birds flew from Moscow to the south simultaneously. The first flock consisted of smaller birds flying at a speed of 50 km/h, while the second flock consisted of ducks flying at a speed of 60 km/h. The ducks arrived at their wintering place 4 hours earlier than the first flock. We need to determine the distance between Moscow and the birds' wintering place.

Solution

Let's assume that the distance between Moscow and the wintering place is D kilometers. We can use the formula distance = speed × time to find the time it took for each flock to reach the wintering place.

For the first flock of smaller birds: **D = 50 ×