Question

Aeroportda bir vaqtda qarama -qarshi yoʻnalishda ikki samolyot uchdi. 2 soatdan keyin ular orasidagi masofa 1500 km ni tashkil qildi . Birinchi samolyot tezligi 400 km/h boʻlsa, ikkinchisining tezligini toping

Answer 1

Ответ:

1500-2=1498

1498+400=1898

Answer 2

The question is about finding the speed of the second plane, given that two planes flew in opposite directions from an airport and the distance between them was 1500 km after 2 hours. The speed of the first plane was 400 km/h.

To solve this problem, we can use the formula for the relative speed of two objects moving in opposite directions:

$$v_r = v_1 + v_2$$

where $v_r$ is the relative speed, $v_1$ is the speed of the first object, and $v_2$ is the speed of the second object.

We know that $v_r$ is equal to the distance divided by the time, so we can write:

$$v_r = \frac{d}{t}$$

where $d$ is the distance and $t$ is the time.

Substituting the given values, we get:

$$v_r = \frac{1500}{2} = 750$$

and

$$v_1 = 400$$

Therefore, we can find $v_2$ by rearranging the formula:

$$v_2 = v_r - v_1$$

Plugging in the values, we get:

$$v_2 = 750 - 400 = 350$$

Hence, the speed of the second plane is 350 km/h.