
1 7/8×1 5/15×1 1/153 3/7×12 5/8×1 25/101Пж 100 баллов срочно


Ответы на вопрос

Пошаговое объяснение:
1 7/8 * 1 5/15 * 1 1/15 = 15/8 * 20/15 * 16/15 = 4/3 = 1 1/3
3 3/7 * 12 5/8 * 1 25/101 = 24/7 * 101/8 * 126/101 = 3*18=54



To solve the given expression, let's break it down step by step:
1. Simplify the multiplication and division operations within each fraction separately.
- 1 7/8 × 1 5/15: - Convert the mixed numbers to improper fractions: - 1 7/8 = (8 × 1 + 7) / 8 = 15/8 - 1 5/15 = (15 × 1 + 5) / 15 = 20/15 - Multiply the fractions: - (15/8) × (20/15) = (15 × 20) / (8 × 15) = 300/120 = 5/2
- 1 1/153 + 3/7 × 12: - Convert the mixed number to an improper fraction: - 1 1/153 = (153 × 1 + 1) / 153 = 154/153 - Multiply the fractions: - (3/7) × 12 = (3 × 12) / 7 = 36/7
- 5/8 × 1 25/101: - Convert the mixed number to an improper fraction: - 1 25/101 = (101 × 1 + 25) / 101 = 126/101 - Multiply the fractions: - (5/8) × (126/101) = (5 × 126) / (8 × 101) = 630/808
2. Add the results of the above calculations:
- 5/2 + 154/153 + 36/7 + 630/808
To simplify this expression further, we need to find a common denominator for all the fractions involved. The common denominator can be found by finding the least common multiple (LCM) of the denominators.
The LCM of 2, 153, 7, and 808 is 21,672.
3. Convert all the fractions to have the common denominator of 21,672:
- (5/2) × (10,836/10,836) = 54,180/21,672 - (154/153) × (14,064/14,064) = 21,336/21,672 - (36/7) × (3,096/3,096) = 110,736/21,672 - (630/808) × (10,836/10,836) = 6,777,180/21,672
4. Add the fractions:
- 54,180/21,672 + 21,336/21,672 + 110,736/21,672 + 6,777,180/21,672
To add fractions, we need to have the same denominator. Since all the fractions already have the same denominator, we can add the numerators:
- (54,180 + 21,336 + 110,736 + 6,777,180) / 21,672
5. Perform the addition:
- (6,963,432) / 21,672 = 321.02
Therefore, the value of the given expression is approximately 321.02.
Please note that the above calculation is based on the given expression and the assumption that the fractions are to be multiplied and added in the order they are presented. If there are any additional instructions or parentheses in the original expression, please provide them for a more accurate calculation.


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