Question

Из двух посёлков одновременно навстречу друг другу выехали два лыжника. Один проходит за час 1/10 всего пути, а другой 1/15 * B * c * e * r * o пути. Через сколько часов они встретятся?​

Answer 1

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Answer 2

Problem Analysis

Two skiers start simultaneously from two different villages and are moving towards each other. One skier covers 1/10 of the total distance in one hour, while the other skier covers 1/15 of the distance in one hour. We need to determine how many hours it will take for them to meet.

Solution

Let's assume that the total distance between the two villages is D.

The first skier covers 1/10 of the total distance in one hour, so their speed can be calculated as (1/10)D per hour.

The second skier covers 1/15 of the total distance in one hour, so their speed can be calculated as (1/15)D per hour.

When the two skiers meet, the sum of the distances covered by both skiers will be equal to the total distance between the villages.

Let's denote the time it takes for them to meet as t.

The distance covered by the first skier in t hours is (1/10)D * t.

The distance covered by the second skier in t hours is (1/15)D * t.

According to the problem, the sum of these distances should be equal to the total distance between the villages, which is D.

Therefore, we can write the equation:

(1/10)D * t + (1/15)D * t = D

Simplifying the equation:

(1/10 + 1/15)D * t = D

To solve for t, we can multiply both sides of the equation by 10 * 15 to eliminate the denominators:

15D + 10D = 150D

Simplifying further:

25D = 150D

Dividing both sides of the equation by 150D:

t = 6 hours

Therefore, it will take 6 hours for the two skiers to meet.

Answer

The two skiers will meet after 6 hours.

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