Question

Решите уравнения ж) 2х+43=4х-65 з)3у-35=7у-28 и) 73-2z=3z+24 к) -х+11=4х-13 л) -13+7у=13у-7 м) z-1=3z-12 в) 3z+2(2z-3) =22-7z г) 3(2m+7) +4=5(m-3) помогите пожалуйста математика 6 класс​

Answer 1

Ответ:

ж) 2x+43=4x-65
2x-4x=-65-43
-2x=-108
x=54

з) 3y-35=7y-28
3y-7y=-28+35
-4y=7

y=-7/4 = $-1\frac{3}{4}$

и) 73-2z=3z+24
-2z-3z=24-73
-5z=-49
z=49/5 $=9\frac{4}{5}$

к) -х+11=4х-13
-x-4x=-13-11
-5x=-24

x=24/5 = $4\frac{4}{5}$

л) -13+7y=13y-7
7y-13y=-7+13
-6y=6
y=-1

м) z-1=3z-12
z-3z=-12+1
-2z=-11
z=11/2 = $5\frac{1}{2}$

в) 3z+2(2z-3)=22-7z
3z+4z-6=22-7z
7z-6=22-7z
7z+7z=22+6
14z=28
z=2

г) 3(2m+7)+4=5(m-3)
6m+21+4=5m-15
6m+25=5m-15
6m-5m-15-25
m=-40

Answer 2

Ответ:

ж) 2х+43=4х-65

2х+43−4х=−65

−2х+43=−65

−2х=−65−43

−2х=−108

х=54

з) 3у−35=7у−28

3у−35−7у=−28

−4у−35=−28

−4у=−28+35

−4у=7

y=7/-4=-1.75
и) 73−2z=3z+24

73−2z−3z=24

73−5z=24

−5z=24−73

−5z=−49

z=-49\-5=9+4\5=9/8
л) -13+7у=13у-7

−13+7у−13у=−7

−13−6у=−7

−6у=−7+13

−6у=6

y=-1

в) 3z+2(2z-3) =22-7z

3z+4z−6=22−7z

7z−6=22−7z

7z−6+7z=22

14z−6=22

14z=22+6

14z=28

z=2

г) 3(2m+7) +4=5(m-3)

6m+21+4=5(m−3)

6m+25=5(m−3)

6m+25=5m−15

6m+25−5m=−15

m+25=−15

m=−15−25

m=−40

Answer 3

Solving Equations

Let's solve the given equations step by step:

a) 2x + 43 = 4x - 65

To solve this equation, we need to isolate the variable x on one side of the equation. We can do this by subtracting 2x from both sides and adding 65 to both sides:

2x + 43 - 2x = 4x - 65 - 2x 43 = 2x - 65

Next, we can add 65 to both sides:

43 + 65 = 2x - 65 + 65 108 = 2x

Finally, we divide both sides by 2 to solve for x:

108/2 = 2x/2 54 = x

Therefore, the solution to the equation 2x + 43 = 4x - 65 is x = 54.

b) 3y - 35 = 7y - 28

To solve this equation, we need to isolate the variable y on one side of the equation. We can do this by subtracting 3y from both sides and adding 28 to both sides:

3y - 35 - 3y = 7y - 28 - 3y -35 = 4y - 28

Next, we can add 28 to both sides:

-35 + 28 = 4y - 28 + 28 -7 = 4y

Finally, we divide both sides by 4 to solve for y:

-7/4 = 4y/4 -7/4 = y

Therefore, the solution to the equation 3y - 35 = 7y - 28 is y = -7/4.

c) 73 - 2z = 3z + 24

To solve this equation, we need to isolate the variable z on one side of the equation. We can do this by subtracting 3z from both sides and adding 73 to both sides:

73 - 2z - 3z = 3z + 24 - 3z 73 - 5z = 24

Next, we can subtract 73 from both sides:

73 - 5z - 73 = 24 - 73 -5z = -49

Finally, we divide both sides by -5 to solve for z:

-5z/-5 = -49/-5 z = 49/5

Therefore, the solution to the equation 73 - 2z = 3z + 24 is z = 49/5.

d) -x + 11 = 4x - 13

To solve this equation, we need to isolate the variable x on one side of the equation. We can do this by adding x to both sides and adding 13 to both sides:

-x + x + 11 = 4x + x - 13 11 = 5x - 13

Next, we can add 13 to both sides:

11 + 13 = 5x - 13 + 13 24 = 5x

Finally, we divide both sides by 5 to solve for x:

24/5 = 5x/5 24/5 = x

Therefore, the solution to the equation -x + 11 = 4x - 13 is x = 24/5.

e) -13 + 7y = 13y - 7

To solve this equation, we need to isolate the variable y on one side of the equation. We can do this by subtracting 13y from both sides and adding 13 to both sides:

-13 + 7y - 13y = 13y - 7 - 13y -13 - 13 = -7

Next, we can add 13 to both sides:

-13 + 13 = -7 + 13 0 = 6

Since 0 does not equal 6, there is no solution to the equation -13 + 7y = 13y - 7.

f) z - 1 = 3z - 12

To solve this equation, we need to isolate the variable z on one side of the equation. We can do this by subtracting z from both sides and adding 12 to both sides:

z - z - 1 = 3z - z - 12 -1 = 2z - 12

Next, we can add 12 to both sides:

-1 + 12 = 2z - 12 + 12 11 = 2z

Finally, we divide both sides by 2 to solve for z:

11/2 = 2z/2 11/2 = z

Therefore, the solution to the equation z - 1 = 3z - 12 is z = 11/2.

g) 3z + 2(2z - 3) = 22 - 7z

To solve this equation, we need to simplify both sides of the equation. Let's start by distributing the 2 on the left side:

3z + 2(2z - 3) = 22 - 7z 3z + 4z - 6 = 22 - 7z

Next, let's combine like terms on both sides:

7z - 6 = 22 - 7z

Now, let's isolate the variable z on one side of the equation. We can do this by adding 7z to both sides and adding 6 to both sides:

7z + 7z - 6 + 6 = 22 - 7z + 7z + 6 14z = 28

Finally, we divide both sides by 14 to solve for z:

14z/14 = 28/14 z = 2

Therefore, the solution to the equation 3z + 2(2z - 3) = 22 - 7z is z = 2.

h) 3(2m + 7) + 4 = 5(m - 3)

To solve this equation, we need to simplify both sides of the equation. Let's start by distributing the 3 on the left side and the 5 on the right side:

3(2m + 7) + 4 = 5(m - 3) 6m + 21 + 4 = 5m - 15

Next, let's combine like terms on both sides:

6m + 25 = 5m - 15

Now, let's isolate the variable m on one side of the equation. We can do this by subtracting 5m from both sides and subtracting 25 from both sides:

6m - 5m + 25 - 25 = 5m - 5m - 15 - 25 m = -40

Therefore, the solution to the equation 3(2m + 7) + 4 = 5(m - 3) is m = -40.

I hope this helps! Let me know if you have any further questions.