Question

Известно, что \m\ = 1, \n\ = 2, ∠(m, n) = 60°. Найдите |2m-3n|.

Answer 1

Ответ:

Пошаговое объяснение:

по теореме cos

|2m-3n|=2×2+6×6-2×2×6×cos60°=

=4+36- 24×1/2=28

Answer 2

Решение:

Given: - \(\m = 1\) - \(\n = 2\) - \(\angle(\m, \n) = 60°\)

We are asked to find \(|2\m - 3\n|\).

First, let's find the values of \(2\m\) and \(3\n\): - \(2\m = 2 \times 1 = 2\) - \(3\n = 3 \times 2 = 6\)

Now, we can find the absolute value of \(2\m - 3\n\): - \(|2\m - 3\n| = |2 - 6| = |-4| = 4\)

So, the value of \(|2\m - 3\n|\) is \(4\).